Wayne named AFC Offensive Player of the Week

INDIANAPOLIS, Ind. (WLFI) - The NFL announced Wednesday that Indianapolis Colts wide receiver Reggie Wayne has been named the AFC Offensive Player of the Week for Week 5. This marks the first time Wayne has earned the award in his career.

Wayne totaled 13 receptions for a career-high 212 yards and scored the game-winning touchdown in the Colts’ 30-27 victory over the Green Bay Packers on Sunday. Down 27-22 with 4:30 remaining in the game, Wayne was instrumental in the Colts’ final drive, catching five passes for 64 yards and scoring the go-ahead touchdown with 35 seconds left.

The 212-yard performance moved Wayne (12,214) past former Colts running back Edgerrin James (12,065) for second place on the franchise’s all-time scrimmage yards list. The yardage total was the second-most for a single game in franchise history behind Raymond Berry’s 224 yards on Nov. 10, 1957 at Washington.

Wayne also moved up three spots on the NFL’s all-time receiving yardage list and surpassed Charlie Joiner (12,146) for 17th place. With his touchdown, Wayne (75) tied Larry Fitzgerald and James Lofton for 27th place on the league’s all-time receiving touchdowns list.

Wayne recorded his 40th 100-yard and second 200-yard receiving game of his career and became only the seventh NFL player since 1990 to record a 200-yard performance in his 10th season or later. Wayne’s 36 receptions for 506 yards are the most he’s ever had through the first four games of a season. He is also averaging an NFL-best 9.0 receptions and 126.5 receiving yards per game this season.

Wayne improved his streak of catching at least one pass to 100 consecutive games. The streak dates back to a Week 1 contest against the New York Giants on September 10, 2006.